Question

How many geometrical isomers are there for $\left[Co\right(N{H}_3{)}_{2}C{l}_4{]}^{-}$ (octahedral) and $\left[AuC{l}_{2}B{r}_2\right]$ (square planar)?

• A. Two cis and trans, no geometrical isomers.
• B. Two cis and trans, two cis and trans.
• C. No geometrical isomers, two cis and trans.
• D. No geometrical isomers, no geometrical isomers.

Answer 1

The correct option is B Two cis and trans, two cis and trans.

For a square planar complex having two types of monodentate ligands, two geometrical isomers are possible, one is cis and other is trans.