Question

How many gram atoms of sulfur are there in 49 g of $H_{2}S{O}_4$ and nitrogen in 126 g of $HN{O}_3$?
Atomic weights of $H=1,N=14,O=16,S=32$.

• A. 0.5 in $H_{2}S{O}_4$; 2 in $HN{O}_3$
• B. 1 in $H_{2}S{O}_4$; 2 in $HN{O}_3$
  
• C. 2 in $H_{2}S{O}_4$; 2 in $HN{O}_3$
  
• D. 2 in $H_{2}S{O}_4$; 1 in $HN{O}_3$
  

Answer 1

The correct option is A

0.5 in $H_{2}S{O}_4$; 2 in $HN{O}_3$

given $49g$ of $H_{2}S{o}_4$

$126g$ of $HN{O}_3$

moles of $H_{2}S{O}_4=\frac{49}{98}=0.5$ mol

moles of $HN{O}_3=\frac{126}{63}=2$ moles

gram atom = no of atoms present in one moles

$49gm$ of $H_{2}S{O}_4$ gram atom = $0.5$ of sulphur

$126gm$ of $HN{O}_3$ gram atom of nitrogen = $2$