Question

How many gram-equivalents of NaOH are required to neutralise 25 cm${}^3$ of a decinormal HCl solution ?

• A. 0.00125
• B. 0.0025
• C. 0.005
• D. 0.025

Answer 1

Answer: (B)

0.0025

For acid-base reactions,

$\underset{\left(HCl\right)}{g-equivalentofacid}=\underset{\left(NaOH\right)}{g-equivalentofbase}$

$\therefore$ g-equivalent of acid = $(25\times {10}^{-3})d{m}^3\times \frac{1}{10}$

$=25\times {10}^{-4}$

$=0.0025$