How many gram ions of $S O_{4}^{- 2}$ are present in 1 gram molecule of $K_{2} S O_{4} . A l_{2} (S O_{4})_{3} .24 H_{2} O$ ?

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Solution

Gram Molecular Weight of $K_{2} S O_{4} . A l_{2} (S O_{4})_{3} .24 H_{2} O$ is $948 g$ .
In it $384 g$ is $S O_{4}^{- 2}$ .
$948 g \to 384 g$ of $S O_{4}^{- 2}$
In $1 g \to ? (x)$
$\Rightarrow x = \frac{1 \times 384}{948} = 0.405 g$
$∴ 0.405 g$ of $S O_{4}^{- 2}$ present in $1 g$ of $K_{2} S O_{4} . A l_{2} (S O_{4})_{3} .24 H_{2} O$

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