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Ideal Gas Equation

How many gram...

Question

How many gram of iron pyrite $(F e S_{2})$ should be burnt completely to produce $S O_{2}$ gas needed to decolorize completely 100ml, 0.12M, $K M n O_{4}$ solution in acidic medium. [Fe= 56]

1.2gm

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1.8gm

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0.9gm

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00.36gm

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Solution

The correct option is D 1.8gm
$2 F e S_{2} + \frac{11}{2} O_{2} \to F e_{2} O_{3} + 4 S O_{2}$
$M n O_{4}^{-} + S O_{2} \to M n^{+ 2} + S O_{3}$
Balance above reaction
$2 M n O_{4}^{-} + 5 S O_{2} + 6 H^{+} \to 2 M n^{+ 2} + 5 S O_{3} + 3 H_{2} O$
Number of mole of $M n O_{4}^{-} = 0.12 \times 100 m l$
$= 12 m M o l$
$2 m o l M n O_{4}^{-}$ required $5 m o l S O_{2}$
$12 m m o l M n O_{4}^{-}$ required $\frac{5}{2} \times 12 m M o l$
$= 30 m M o l$
Now,
$4 m o l S O_{2}$ required $2 m o l F e S_{2}$
$30 m M o l S O_{2}$ required $\frac{2}{4} \times 30 m o l$
$15 m m o l$
Amount of $F e S_{2} = 15 \times 10^{- 3} \times (56 + 64)$
$= 120 \times 15 \times 10^{- 3}$
$= 1.8 g$

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