Question

How many grams are there in $3.3\text{moles}$ of aluminum?

Answer 1

Step 1: Given information

$3.3\text{moles}$ of Aluminum $\left(\mathrm{Al}\right)$

Step 2: Understanding Mole Concept

• It is defined as the amount of substance that constitutes the same number of elementary particles, such as ions, atoms, or molecules as the total number of atoms present in $12\mathrm{g}$ of Carbon-12 $\left({\mathrm{C}}^{12}\right)$.
• One mole of any chemical species contains $6.022\times {10}^{23}$ particles.
• 1 mole of any species has mass equal to its gram atomic mass.

Step 3: Calculation of required mass of aluminum in grams

• Gram atomic mass of aluminum is $27\text{g}$.
• Thus, mass of $1\text{mole}$ of aluminum is $27\text{g}$
• $3.3\text{moles}$ of aluminum will have $27\text{g×3.3 =89.1 g}$ mass.

Hence, $3.3\text{moles}$ of aluminum contain $89.1\text{g}$.