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Concentration Terms

How many gram...

Question

How many grams $N a O H$ are present in $250 m L$ of $0.5 M$ $N a O H$ solution?

7.32 g

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3.8 g

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5 g

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0.5 g

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Solution

The correct option is C $5 g$
No of moles (n) = $\frac{M o l a r i t y \times V_{m L}}{1000}$

Given:

$M = 0.5 M$
$V_{m L} = 250 m L$

Therefore, $n = \frac{0.5 \times 250}{1000} = \frac{125}{1000} = 0.125 m o l$

Molar mass of $N a O H$ = $40 g$

Mass of $N a O H$ = $0.125 \times 40 = 5 g$

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