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Question

How many grams of calcium lactate pentahydrate would be recovered from 1 g of anhydrous salt?

A
1.41
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B
1.00
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C
1.27
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D
1.51
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Solution

The correct option is A 1.41
As we know, molecular weight of anhydrous calcium lactate =218 g/mol.
Number of moles in 1 g anhydrous salt =1218=4.587×103.
1 mol pentahydrate salt would be recovered from 1 mol anhydrous salt.
Thus, number of moles of pentahydrate salt
=4.587×103.
Molecular weight of pentahydrate salt = Molecular weight of anhydrous salt + Weight of 5 water molecules =218+18×5=308 g/mol
Thus, mass of pentahydrate salt =308×(4.587×103)=1.41 g.

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