Question

How many grams of $C{H}_{3}OH$ should be added to water to prepare $150$ml solution of $2MC{H}_{3}OH$?

• A. $9.61\times {10}^3$
• B. $2.4\times {10}^3$
• C. $9.61$
• D. $2.4$

Answer 1

Answer: (C)

$9.61$

Given: $150ml$ of $2.0M$ $C{H}_{3}OH$ is to be prepared.

Number of moles= $M\times VolumeinL=2.0\times 0.150=0.3$

Molar mass of $C{H}_{3}OH=32.04g/mol$

$\therefore$ Weight of $C{H}_{3}OH$ to be added= $32.04\times 0.3=9.61g$