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Question

How many grams of CH3OH should be added to water to prepare 150ml solution of 2MCH3OH?

A
9.61×103
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B
2.4×103
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C
9.61
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D
2.4
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Solution

The correct option is B 9.61
Given: 150ml of 2.0M CH3OH is to be prepared.

Number of moles= M×Volume inL=2.0×0.150=0.3

Molar mass of CH3OH=32.04g/mol

Weight of CH3OH to be added= 32.04×0.3=9.61g

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