How many grams of chlorine is needed to combine with 23 gm of sodium to make 58.5 gm of sodium chloride?

23 gm

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35.5 gm

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58.5 gm

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70 gm

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Solution

The correct option is C 35.5 gm
The reaction is: $2 N a + C l_{2} \to 2 N a C l$
23 gm of sodium $=$ 1 mole
Moles of sodium chloride= $\frac{58.5}{58.5} = 1$
So, one mole of $N a$ will react with 0.5 mole $= 0.5 \times 71 = 35.5 g m C l_{2}$

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How many grams of chlorine is needed to combine with 23 gm of sodium to make 58.5 gm of sodium chloride?

The correct option is C 35.5 gmThe reaction is: 2Na+Cl2→2NaCl23 gm of sodium= 1 mole Moles of sodium chloride=58.558.5=1So, one mole of Na will react with 0.5 mole =0.5×71=35.5 gm Cl2

The correct option is C 35.5 gm
The reaction is: $2 N a + C l_{2} \to 2 N a C l$
23 gm of sodium $=$ 1 mole
Moles of sodium chloride= $\frac{58.5}{58.5} = 1$
So, one mole of $N a$ will react with 0.5 mole $= 0.5 \times 71 = 35.5 g m C l_{2}$