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Question

How many grams of commercial sodium hydroxide containing 75% Na2O are required to prepare 600 g of a 15% sol. of NaOH?

A
56
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B
93
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C
34
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D
87
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Solution

The correct option is B 93
Let x gm of Na2O are there.
Pure Na2Ox×75100=3x4
Pure NaOH=600×15100=90 gm
Moles =9040=2.25 moles
Na2O+H2O2NaOH
1.125 moles 2.25 moles
3x4×62=1.125
x=93 gm

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