How many grams of concentrated sulphuric acid $(80 % w / w)$ should be used to prepare $100 m L$ of one molar $H_{2} S O_{4}$ ?

10 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12.25 g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

15 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

17.5 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $12.25 g$
Grams of concentrated sulphuric acid needed
= $1 N \times 49 \times 0.250 l i t e r = 12.25 g r a m s .$
For example, if we take $6.9 m L$ of concentrated sulfuric acid and diluted it to $250 m L$ , you would have a $1 N H_{2} {S O}_{4}$ solution.
Conclusion: Hence, the option $(B)$ is correct.

Suggest Corrections

Similar questions

250

2

H N O_{3}

70 %

H N O_{3}

H N O_{3}

H N O_{3}

H N O_{3}

H N O_{3}

Join BYJU'S Learning Program