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Question

How many grams of Cr are deposited in the electrolysis of a solution of Cr(NO3)3 in the same time that it takes to deposit 0.54 g of Ag in a silver coulometer arranged in series with the Cr(NO3)3 cell?
(Given your answe upto two decimal)
(Atomic weight: Cr=52.0 u; Ag=108 u)

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Solution

According to Faraday’s second law-
WE
wAgwcr=EAgECr.....(i)
Now, Ag++eAg
Equivalent weight of Ag, EAg
=Atomiuc mass of AgNumber of e gain or loss
=1081=108
For, Cr+3+3eCr
Equivalent weight of Cr, ECr
=Atomic mass of CrNumber of e gain or loss
=523
Putting the values in eq (i);
0.54wcr=108523
Wcr=52×0.543×108=0.0866 g

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