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Question

How many grams of $H_{2} S O_{4}$ are present in $0.25 g$ mole of $H_{2} S O_{4}$ ?

2.45

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24.5

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0.25

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245

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Solution

The correct option is C $24.5$
$M o l e s o f H_{2} {S O}_{4} = 0.25 M o l e c u l a r m a s s (M) o f H_{2} {S O}_{4} = 2 + 32 + 16 \times 4 = 34 + 64 = 98 a m u n o . o f g r a m s (w) = ? w e h a v e, n o . o f m o l e s = \frac{w}{M} W = n o . o f m o l e s \times M = 0.25 \times 98 = 24.5 g o f H_{2} {S O}_{4}$

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