Question

How many grams of $H_{2}S{O}_4$ are present in $0.25g$ mole of $H_{2}S{O}_4$?

• A. $2.45$
• B. $24.5$
• C. $0.25$
• D. $245$

Answer 1

Answer: (B)

$24.5$

$Molesof{H}_2{SO}_4=0.25Molecularmass\left(M\right)of{H}_2{SO}_4=2+32+16\times 4=34+64=98amuno.ofgrams\left(w\right)=?wehave,no.ofmoles=\frac{w}{M}W=no.ofmoles\times M=0.25\times 98=24.5gof{H}_2{SO}_4$