Question

How many grams of $H_{3}P{O}_4$ is required to completely neutralize $120$ g of $NaOH$?

• A. $49$
• B. $98$
• C. $196$
• D. $9.8$

Answer 1

Answer: (B)

$98$

The balanced chemical equation is as follows:
$H_{3}P{O}_4+3NaOH\to N{a}_{3}P{O}_4+3H_{2}O$.

Here, 1 mole $H_{3}P{O}_4$ is required to neutralize 3 moles of $NaOH$.

One mole ($98$ g) of phosphoric acid will neutralize $3$ moles ($3\times 40=120$ g) of sodium hydroxide.