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Stoichiometric Calculations

How many gram...

Question

How many grams of HCl is needed for complete reaction with $69.6$ g $M n O_{2}$ ?

$H C l + M n O_{2} \to M n C l_{2} + H_{2} O + C l_{2}$

116.8 g

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121.4 g

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167.5 g

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200.8 g

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Solution

The correct option is A 116.8 g
The balanced chemical equation is $M n O_{2} + 4 H C l \to C l_{2} + M n C l_{2} + 2 H_{2} O$ .

Thus, $1$ mole of $M n O_{2}$ will react with $4$ moles of HCl.

The molar masses of $M n O_{2}$ and HCl are $86.94$ g/mol and $36.5$ g/mol respectively.

The amount of HCl that will react with $69.6$ g of $M n O_{2}$ is $\frac{36.5 \times 4}{86.94} \times 69.6 = 116.8 g m$ .

Hence, option A is correct.

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Similar questions

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M n O_{2} + 4 H C l \to M n C l_{2} + C l_{2} + 2 H_{2} O

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