wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

How many grams of HCl is needed for complete reaction with 69.6 g MnO2?


HCl+MnO2MnCl2+H2O+Cl2

A
116.8 g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
121.4 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
167.5 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
200.8 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 116.8 g
The balanced chemical equation is MnO2+4HClCl2+MnCl2+2H2O.

Thus, 1 mole of MnO2 will react with 4 moles of HCl.

The molar masses of MnO2 and HCl are 86.94 g/mol and 36.5 g/mol respectively.

The amount of HCl that will react with 69.6 g of MnO2 is 36.5×486.94×69.6=116.8 gm.

Hence, option A is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Stoichiometric Calculations
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon