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Question

How many grams of hydrogen gas is required to produce 4.8 mol of ammonia on a reaction with an excess of nitrogen?

A
7.2 g
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B
14.4 g
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C
17 g
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D
15 g
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Solution

The correct option is B 14.4 g
The balanced chemical equation is:
N2+3H22NH3

From stoichiometry,
2 mol of NH3 is produced from 3 mol of H2.
4.8 mol of NH3 will be produced from = 32×4.8 = 7.2 mol of H2
mass of H2=7.2×2=14.4 g

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