Question

How many grams of KOH are required to make 250 mL of a 6 M solution of KOH?

• A. 84 g
• B. 56 g
• C. 840 g
• D. 112 g

Answer 1

The correct option is A 84 g

$Molarity=\frac{\text{moles of solute KOH}}{\text{total volume of solution in mL}}\times 1006M=\frac{\text{moles of solute}}{250}\times 1000$
Moles of solute= $1.5$ moles
Mass of 1.5 moles of $KOH=1.5\times 56=84$ g