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Stoichiometric Calculations

How many gram...

Question

How many grams of methane are required to produce $22 g C O_{2}$ by combustion?
$C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O$

8 g

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3 g

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4 g

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5 g

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Solution

The correct option is A $8 g$
$C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O$

Moles of $C O_{2} = \frac{22}{44} = 0.5 mol$
1 mol of $C O_{2}$ is produced from 1 mol of $C H_{4}$ .
So, 0.5 mol of $C O_{2}$ will be produced from 0.5 mol of $C H_{4}$ .
Mass of $C H_{4}$ formed = Moles $\times$ Molar mass
Mass of $C H_{4}$ formed = $0.5 mol \times 16 g/mol = 8 g$

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$C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O$

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