How many grams of molecules of $H_{2} {SO}_{4}$ are present in 4.9 g of the acid?

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Solution

Here, the Gram molecular mass of $H_{2} {SO}_{4}$ = $2 \times 1 + 32 + 4 \times 16$
=98 gm
Therefore 98 gm of $H_{2} {SO}_{4}$ =1 gram of molecule or mole
So,4.9 g of $H_{2} {SO}_{4}$ = $\frac{4.9}{98}$ gram of molecule or mole
= $0.05 g r a m m o l e c u l e$

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