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Stoichiometry

How many gram...

Question

How many grams of $N a_{2} S O_{4}$ can be produced from 260 gm of 90% pure $N a C l$ when treated with excess of $H_{2} S O_{4}$ ?

255 gm

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173 gm

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214 gm

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284 gm

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Solution

The correct option is D 284 gm
$2 N a C l + H_{2} S O_{4} \to N a_{2} S O_{4} + 2 H C l$
$117 g m 142 g m$
Since,
$117 g m N a C l produces 142 g m N a_{2} S O_{4} =$
$1 g m N a C l produces = \frac{142}{117} g m N a_{2} S O_{4}$
So, 90% pure $N a C l$ of 260 gm has ( $260 \times \frac{90}{100} = 234 g m$ ) $N a C l$ and will produce = $\frac{142}{117} \times (234) = 284 g m N a_{2} S O_{4}$

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