Question

How many grams of $NaOH$ is required to prepare 1500 mL of a 0.1 N $NaOH$ solution?

• A. 10 g
• B. 6 g
• C. 8 g
• D. 15 g

Answer 1

The correct option is B 6 g

$\text{Normality (N)}=\frac{\text{weight of NaOH}}{\text{equivalent weight of NaOH}\times \text{volume of solution (mL)}}\times 1000$

$\text{Weight of NaOH required}=\frac{\text{N}\times \text{equivalent weight of NaOH}\times \text{volume}}{1000}$
Since the n- factor for $NaOH=1$, the equivalent weight of $NaOH=40$ g
$\text{Weight of NaOH required}=\frac{0.1\times 40\times 1500}{1000}$
Weight of $NaOH=6$ g