How many grams of NaOH must be dissolved in 1 $L^{- 1}$ of the solution to give it a pH value of 12?

0.20

L^{- 1}

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0.40

L^{- 1}

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0.10

L^{- 1}

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1.2

L^{- 1}

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Solution

The correct option is B $0.40$ g $L^{- 1}$
$p H = - l o g [H^{+}]$
Here, $p H = 12$ so $p O H = 14 - 12 = 2$
$[O H^{-}] = 10^{- 2}$
Let $x$ gm of NaOH is dissolved then
$\frac{x}{40} = 0.01 ∴ x = 0.40 g m$

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How many grams of NaOH must be dissolved in 1 L−1 of the solution to give it a pH value of 12?

The correct option is B 0.40 g L−1pH=−log[H+]Here, pH=12 so pOH=14−12=2[OH−]=10−2Let x gm of NaOH is dissolved thenx40=0.01∴x=0.40gm

How many grams of NaOH must be dissolved in 1 $L^{- 1}$ of the solution to give it a pH value of 12?

The correct option is B $0.40$ g $L^{- 1}$
$p H = - l o g [H^{+}]$
Here, $p H = 12$ so $p O H = 14 - 12 = 2$
$[O H^{-}] = 10^{- 2}$
Let $x$ gm of NaOH is dissolved then
$\frac{x}{40} = 0.01 ∴ x = 0.40 g m$