How many grams of $N a O H$ must be dissolved in 1g of 1L of solution to have a solution of $p H = 12$ . Find molarity.

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Solution

Here pH is 12
$p H + p O H = 14$
therefore, $p O H = 2$
$p O H = - l o g [O H^{-}]$
$l o g [O H^{-}] = 2$
$O H^{-} = 0.01 m o l (L)^{-}$
Therefore there are 0.01moles of $N a O H$ in 1L of Solution
Mass of $N a O H$ =Molecular mass $\times n = 40 g (m o l)^{-} \times 0.01 m o l = 0.4 g$

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