How many grams of $N a O H$ should be added in $100$ ml to get $2$ M $N a O H$ aqueous solution?
(Atomic weight of $N a O H$ is $40$ gm/mol).

2

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80

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8

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40

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Solution

The correct option is B $8$ gm
Suppose $N a O H$ added $= x$ gm

Molarity $= 2 M$ --------- (given)

The volume of the solution $= 100 / 1000$ (in litre)

$2 = \frac{x \times 1000}{40 \times 100}$

$\Rightarrow x = 8 g .$

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