How many grams of oxygen gas will be needed for complete combustion of $2 m o l e s$ of $3^{r d}$ member of alkyne series?

186 g

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256 g

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352 g

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372 g

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Solution

The correct option is C $352 g$
$2 C_{4} H_{6} + 11 O_{2} \to 8 C O_{2} + 6 H_{2} O$
For $2$ mole of hydrocarbon, $11$ moles of $O_{2}$ is required
$∴ 11 m o l e s = 11 \times 32 = 352 g$ .

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