Dear student,
The reaction of Mg with oxygen to form MgO can be written as:
2 Mg + O2 ---> 2 MgO
Given:
Mass of Mg = 96 g
Molar mass of Mg = 24.3 g/mol
Moles of Mg = mass / molar mass
= 96 g / 24.3 g/mol
= 3.95 moles
According to balanced chemical reaction:
2 moles of Mg react with = 1 mole of oxygen
3.95 moles of Mg will react with = ( ½ ) x 3.95 = 1.975 moles of oxygen
Mass of oxygen = Moles x molar mass
= 1.975 moles x 32 g/mol
= 63.2 g of oxygen
Answer = 63.2 g of oxygen
Regards