How many grams of silver will electroplate when four moles of electrons are used in silver nitrate solution?

108

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216

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324

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432

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540

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Solution

The correct option is D $432$ g
$432$ grams of silver will electroplate when four moles of electrons are used in silver nitrate solution.

$A g^{+} + e^{-} \to A g$

1 mole of electrons will electroplate 1 mole of $A g$ .

Thus 4 moles of electrons will electroplate 4 moles of $A g$ .

The molar mass of $A g$ is 108 g/mol.

4 moles of $A g$ corresponds to a mass of $4 \times 108 = 432$ grams.

Hence the correct option is D.

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