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Byju's Answer
Standard X
Chemistry
Ideal Gas Equation
How many gram...
Question
How many grams of sodium bicarbonate are required to neutralize 10.0 ml of 0.902 M vinegar?
A
8.4g
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B
1.5g
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C
0.75g
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D
1.07g
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Solution
The correct option is
B
0.75g
C
H
3
C
O
O
H
+
N
a
H
C
O
3
→
C
H
3
C
O
O
N
a
+
H
2
O
+
C
O
2
Equivalents of
C
H
3
C
O
O
H
=
M
o
l
a
r
i
t
y
×
v
o
l
u
m
e
×
n
f
=
0.902
×
10
×
10
−
3
Equivalents of
N
a
H
C
O
3
required
=
M
o
l
e
s
×
n
f
=
0.902
×
10
×
10
−
3
Moles of
N
a
H
C
O
3
=
9.02
×
10
−
3
Weight of
N
a
H
C
O
3
=
9.02
×
10
−
3
×
84
=
0.75
g
r
a
m
s
Suggest Corrections
0
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