Question

# How many grams of the concentrated nitric acid solution is required to prepare $$250mL$$ of $$2.0M$$ nitric acid solution? (Concentration of $$H{NO}_{3}$$ is $$70\%$$)

A
45g
B
90g
C
70g
D
54g

Solution

## The correct option is A $$45g$$The required number of moles= $$=(\dfrac { 250 }{ 1000 } )×2=0.5$$moles                               (no. of moles=molarity × volume)so,required mass of $$HN{ O }_{ 3 }=0.5×63=31.5grams$$            (given mass=no. of moles × molar mass)Given,70 grams of $$HN{ O }_{ 3 }$$ are present in 100 grams of the solution,so,1 gram will be present in $$\dfrac { 100 }{ 70 }$$ grams of solutionhence 31.5 grams will be present in $$\dfrac { 100 }{ 70 } ×31.5$$ grams of solution.so the amount of concentrated nitric acid solution used is 45 gramsChemistry

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