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how many grams of Zn are required to liberate 2.24 litres of hydrogen from sulphuric acid

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$Z n + H_{2} S O_{4} \to Z n S O_{4} + H_{2} 65.38 g o f h y d r o g e n r e a c t s w i t h s u l p h u r i c a c i d g i v e s 1 m o l e o f h y d r o g e n = 22.4 L o f h y d r o g e n 2.24 L o f h y d r o g e n i s p r o d u c e d f r o m = \frac{65.38}{22.4} \times 2.24 = 6.538 g$

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