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Question

How many integers greater than 1000 can be formed from the digits 0, 2, 3, and 5 if no digit is repeated in any number?

A
9
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B
18
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C
27
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D
36
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E
72
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Solution

The correct option is B 18
  • First digit can be filled in 3 ways (0 cannot be first digit because it should be four digit number)
  • second digit can be filled in 3 ways
  • Third digit can be filled in 2 ways
  • Fourth digit can be filled in 1 way
  • Therefore total number of distinct numbers will be 3×3×2×1=18

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