How many integral solution does the equation $4 x - 1 = 8$ has?

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Solution

Given equation: $4 x - 1 = 8$
On transposing $- 1$ from LHS to RHS, we get,
$4 x = 8 + 1$
$\Rightarrow 4 x = 9$

On dividing both the sides by 4, we get,
$x = \frac{9}{4}$
We know that, $\frac{9}{4}$ is not an integer.
Therefore, the equation $4 x - 1 = 8$ has no integral solution.

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