How many integral solutions are there for the equation A+B+C = 10 where A≥1,B≥2,C≥3?
This is a question based on S‘aD with a varying lower limit.
Take out 1+2+3=6 from the RHS. Equation changes to
A+B+C = 4. Answer will the arrangement of 4 zeroes and 2 ones = 6C2