How many interference bands can be observed on the screen?

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Solution

The correct option is A 5
We have,
$N = \frac{l}{β}$
where $n$ is the number of fringes and $L$ is the width of the interference pattern
From the figure we have,
$\frac{L}{d} = \frac{b}{a}$
$⟹ L = \frac{b}{a} \times d = \frac{4}{1} \times 2 \times 10^{- 3} = 8 \times 10^{- 3} m$
Hence $N = \frac{8 \times 10^{- 3}}{15 \times 10^{- 4}} = 5.3$

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How many interference bands can be observed on the screen?

The correct option is A 5We have,N=lβwhere n is the number of fringes and L is the width of the interference patternFrom the figure we have,Ld=ba⟹L=ba×d=41×2×10−3=8×10−3mHence N=8×10−315×10−4=5.3