How many ions are obtained in the given complexes due to ionisation in aqueous solution? $C u C l_{2} \cdot 4 N H_{3}$

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Solution

Complex will dissociate as
$[C u (N H_{3})_{4}] C l_{2} ⇌ [C u (N H_{3})_{4}]^{2 +} + 2 C l^{-}$ ;
So total 3 ions.

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How many ions are obtained in the given complexes due to ionisation in aqueous solution?CuCl2⋅4NH3

Complex will dissociate as [Cu(NH3)4]Cl2⇌[Cu(NH3)4]2++2Cl−; So total 3 ions.

How many ions are obtained in the given complexes due to ionisation in aqueous solution? $C u C l_{2} \cdot 4 N H_{3}$

Complex will dissociate as
$[C u (N H_{3})_{4}] C l_{2} ⇌ [C u (N H_{3})_{4}]^{2 +} + 2 C l^{-}$ ;
So total 3 ions.