How many ions are produced from the complex, $[C o (N H_{3})_{6} C l_{2}]$ in solution?

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Solution

The complex will dissociate in a aqueous solution to produce 3 ions.
$C o (N H_{3})_{6} C l_{2} a q \to [C o (N H_{3})_{6}]^{2 +} + 2 C l^{-}$
Thus, correct

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How many ions are produced from the complex Co(NH₃)₆Cl₂ in solution?

(i) 6

(ii) 4

(iii) 3

(iv) 2

[C o (N H_{3})_{6}] C l_{3}

_{4}

_{6}

C u C l_{2} \cdot 4 N H_{3}

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