How many isomeric compounds can be represented by formula $C_{4} H_{10} O$ ?

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Solution

The correct option is B 7
The isomers must be alcohols & ethers.
For alcohols,
(1) $C H_{3} C H_{2} C H_{2} C H_{2} O H$ $b u t a n - 1 - o l$
(2) $C H_{3} - C H_{2} - C H | - C H_{3}$ $b u t a n - 2 - o l$
$O H$
(3) $C H_{3} - C H | - C H_{2} - O H$ $2 - m e t h y l p r o p a n - 1 - o l$
$C H_{3}$
(4) $C H_{3}$
$C H_{3} - | C | - O H$ $2 - m e t h y l p r o p a n - 2 - o l$
$C H_{3}$

For ethers,
(5) $C H_{3} C H_{2} C H_{2} O C H_{3}$ $1 - m e t h o x y p r o p a n e$
(6) $C H_{3} C H_{2} O C H_{2} C H_{3}$ $e t h o x y e t h a n e$
(7) $C H_{3} - C H | - O C H_{3}$ $2 - m e t h o x y p r o p a n e$
$C H_{3}$

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