How many isomers are possible in $C_{3} H_{5} C l$ including geometrical isomers?

2

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3

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4

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5

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Solution

The correct option is C $5$
From the image, it is clear that if we count the two geometrical isomers separately we have 5 possible isomers of the given Compound.

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Similar questions

C_{3} H_{5} C l

[A l (C_{2} O_{4})_{3}]^{3 -}

_{3}

_{2}

_{2}

^{+}

3 - B r o m o - 5 - i o d o m e t h y l c y c l o h e x a n e

How many geometrical isomers are possible in the following coordination entities?
(1). ${[C r {(C_{2} O_{4})}_{3}]}_{3}^{3 -}$

(2). $[C o {(N H_{3})}_{3} C l_{3}]$

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