How many isomers (including stereoisomers) can be obtained by free radical chlorination of 2,2,4− trimethylpentane?
A
3
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B
4
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C
5
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D
6
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Solution
The correct option is D6 free radical chlorination of 2,2,4−2,2,4− trimethylpentane gives total 6 isomers. Four type of radicals possible out of which two chlorination product have chiral carbon so both R and S form possible. In all of the above products chlorine is added at free radical carbon.