How many kilograms will a man working at the power of 100 W, be able to lift at
constant speed of 1 $m s^{- 1}$ vertically ? $(g = 10 m s^{- 2})$

100 k g

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1 k g

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10 k g

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0.1 k g

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Solution

The correct option is C $10 k g$
Power $= \frac{w o r k d o n e o r e n e r g y}{t i m e} = \frac{m g h}{t} = m . g . (\frac{h}{t})$
Here $\frac{h}{t} =$ speed
Therefore, $m = \frac{p o w e r}{g \times s p e e d} = \frac{100}{10 \times 1} = 10 k g$

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