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Question

How many kJ of energy is spent when a current of 4 amp passes for 200 second under a potential of 115 V ?

A
52 kJ
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B
72 kJ
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C
82 kJ
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D
92 kJ
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Solution

The correct option is D 92 kJ
ΔG=nFE=QE=4×200×115×103 kJ ΔG=92kJ
The energy spent by the source = 92 kJ

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