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Question

How many liters of a solution that is 15 percent salt must be added to 5 liters of a solution that is 8 percent salt so that the resulting solution is 10 percent salt?

A
3
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B
5
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C
2
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D
4
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Solution

The correct option is A 2
Let n represent the number of liters of the 15 % solution. The amount of salt in the 15 % solution [0.15n] plus the amount of salt in the 8 % solution [(0.08)(5)] must be equal to the amount of salt in the 10 % mixture [0.10(n + 5)] Therefore,
0.15n+0.08(5)=0.10(n+5)
15n+40=10n+50
5n=10
n=2 liters
Two liters of the 15 % salt solution must be added to the 8 % solution to obtain the 10 % solution.

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