How many liters of milk can a hemispherical bowl of diameter $10.5 c m$ hold ?

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Solution

Volume of hemisphere bowl $= \frac{2}{3} π r^{3}$

Diameter $= 10.5$ cm

Radius $= \frac{10.5}{2}$ cm

Volume $= \frac{2}{3} \times \frac{22}{7} \times \frac{10.5}{2} \times \frac{10.5}{2} \times \frac{10.5}{2}$

$= \frac{5.5 \times 10.5 \times 10.5}{2} c m^{3}$

Volume $= 303.1875 c m^{3} ≅ 0.3$ L

The bowl can hold $0.3$ litres of milk.

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