How many litres of water must be added to 1 L of an aqueous solution of $H C l$ with a pH of 1 to create an aqueous solution with pH of 2?

0.1 L

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0.9 L

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2.0 L

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9.0 L

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Solution

The correct option is D 9.0 L
$p H = 1 ∴ [H^{+}] = 10^{- 1} = 0.1 M$
$p H = 2 ∴ [H^{+}] = 10^{- 2} = 0.01 M$
For dilution of HCl, $M_{1} V_{1} = M_{2} V_{2}$
$0.1 \times 1 = 0.01 \times V_{2}$
$V_{2} = 10 L$
Volume of water to be added = 10 - 1 = 9 L

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