How many litres of water must be added to a litre of an aqueous solution of $H C l$ with a $p H$ of $1$ to create an aqueous solution with $p H$ of $2$ ?

0.9 L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.0 L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9.0 L

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.1 L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $9.0 L$
Initial $p H = 1$ , i.e. $[H^{+}] = 0.1 m o l e / l i t r e$

New $p H = 2$ , i.e. $[H^{+}] = 0.01 m o l e / l i t r e$
$V_{1} = 1 l i t$
In case of dilution:

$M_{1} V_{1} = M_{2} V_{2}$

$0.1 \times 1 = 0.01 \times V_{2}$

$V_{2} = 10$ litre

Volume of water added V $= V_{2} - V_{1} = 9$ litre.

Suggest Corrections

Similar questions

How many litres of water must be added to 1 litre of an aqueous solution of HCl with a pH of 1 to create an aqueous solution with pH of 2?

H C l

1

H C l

p H

2

3

Join BYJU'S Learning Program