How many miles of calcium carbonate are present in 10g of the substance
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Solution
CaCO3: From the Periodic Table... Ca atomic mass = 40. C = 12 and, O3 = 16 x 3 = 48. Added together, the mol.mass = 100g/mol. Mass / mol.mass = moles. 10g / 100g/mol = 0.10 moles