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Question

How many miles of calcium carbonate are present in 10g of the substance

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Solution

CaCO3: From the Periodic Table...
Ca atomic mass = 40.
C = 12 and, O3 = 16 x 3 = 48.
Added together, the mol.mass = 100g/mol.
Mass / mol.mass = moles.
10g / 100g/mol = 0.10 moles

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