Question

How many milliliters of $0.250M$ $NaOH$ is required to neutralize $30.4mL$ of $0.152M$ $HCl$?

• A. 10.0 mL
• B. 25.0 mL
• C. 5.9 mL
• D. 18. mL
• E. 15.5 mL

Answer 1

Answer: (D)

18. mL

We know that

Concentration = $\frac{Amountofsubstanceinmoles}{Volumeofsolution}$

Explanation:

Moles of $HCl$ = $30.4\times {10}^{-3}\times 0.152=4.62\times {10}^{-3}$

We need an equivalent quantity of sodium hydroxide;

$0.250$ sodium hydroxide is available.

So,

$\frac{4.62\times {10}^{-3}}{0.250}$ = 18.3 ml

D is correct