How many millilitres of 1M ${H_{2} S O}_{4}$ will be neutralised by 10ml of 1M NaOH solution?

10

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20

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2.5

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5

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Solution

The correct option is D $5$
The reaction is,

$H_{2} S O_{4} + 2 N a O H \to N a_{2} S O_{4} + 2 H_{2} O$

Using normality,
$2 \times M_{H_{2} S O_{4}} \times V_{r e q} = 1 \times M_{N a O H} \times V_{N a O H}$

$2 V_{r e q} = 10 m l$

$\Rightarrow V_{r e q} = 5 m l$

Option D is correct.

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How many millilitres of 1M H2SO4 will be neutralised by 10ml of 1M NaOH solution?

The correct option is D 5The reaction is,H2SO4+2NaOH→Na2SO4+2H2OUsing normality,2×MH2SO4×Vreq=1×MNaOH×VNaOH2Vreq=10ml⇒Vreq=5ml Option D is correct.

How many millilitres of 1M ${H_{2} S O}_{4}$ will be neutralised by 10ml of 1M NaOH solution?

The correct option is D $5$
The reaction is,

$H_{2} S O_{4} + 2 N a O H \to N a_{2} S O_{4} + 2 H_{2} O$

Using normality,
$2 \times M_{H_{2} S O_{4}} \times V_{r e q} = 1 \times M_{N a O H} \times V_{N a O H}$

$2 V_{r e q} = 10 m l$

$\Rightarrow V_{r e q} = 5 m l$

Option D is correct.